LSAT Practice Test

If a child plays game S before game T, how many games are played between S and T?

1. 0

2. 1

3. 2

4. 3

The correct answer is: 2

If a child plays game S before game T, then there are two games played between S and T. This is because the child plays game S first, then there are two other games played before reaching game T. Therefore, the correct answer is C. The other options are incorrect because if there were 0 games played between S and T, then the child would play game S and immediately play game T, which contradicts the given order. If there were 1 game played between S and T, then the child would play game S, then one game, and finally game T, which also does not align with the given order. If there were 3 games played between S and T, this would mean there are too many games played between them according to the given order.