LSAT Practice Test

Either Y or Z translates to:

1. If Y --> Z

2. If Z --> Y

3. If ~Y --> Z

4. If ~Z --> Y

The correct answer is: If ~Y --> Z

In logical terms, the statement "Either Y or Z" can be represented as "Y or Z," meaning at least one of Y or Z must be true. To represent this in conditional logic, if Y is false (~Y) then it must be the case that Z is true. Therefore, the correct translation of "Either Y or Z" is "If ~Y, then Z," which is accurately represented in option C. Options A and B do not account for the case when Y is false and are therefore incorrect translations. Option D is also incorrect because it states that if Z is false, then Y must be true, which does not accurately represent the original statement.