LSAT Practice Test

What is the minimum number of performances that will occur before J performs?

1. 3

2. 4

3. 5

4. 6

The correct answer is: 4

In this question, we are looking for the minimum number of performances that will occur before J performs. To determine this, we need to consider the sequence in which the performances take place. We are told that J performs immediately after K performs, and K performs immediately after L performs. Therefore, the sequence of performances will be: L, K, J. This means that a minimum of 3 performances (L, K, J) must occur before J performs. So, the correct answer is B. Option A is incorrect because it does not account for the fact that K must perform before J. Option C is incorrect because it is too high based on the given sequence of performances. Option D is incorrect for the same reason as option C, it is too high based on the given sequence of performances.